the-rate-constant-for-the-radioactive-decay-of-berkelium-248-248bk-and-seaborgiu-1

Question

The first-order rate constant for the radioactive decay of Berkelium-248 (²⁴⁸Bk) and Seaborgium-260 (²⁶⁰Sg) is 0.0292 h $k = M^{- n + 1} \cdot t^{- 1}$ ¹ and 0.173 ms $k = M^{- n + 1} \cdot t^{- 1}$ ¹, respectively. Which sample decays at a faster rate?

Accepted Answer

Seaborgium-260 has a faster decay rate

Answer

Berkelium-248 has a faster decay rate

Answer

Seaborgium-260 and Berkelium-248 have equal decay rate

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The first-order rate constant for the radioactive decay of Berkelium-248 (²⁴⁸Bk) and Seaborgium-260 (²⁶⁰Sg) is 0.0292 h $k = M^{- n + 1} \cdot t^{- 1}$ ¹ and 0.173 ms $k = M^{- n + 1} \cdot t^{- 1}$ ¹, respectively. Which sample decays at a faster rate?

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The first-order rate constant for the radioactive decay of Berkelium-248 (248Bk) and Seaborgium-260 (260Sg) is 0.0292 h−1 and 0.173 ms−1, respectively. Which sample decays at a faster rate?

The first-order rate constant for the radioactive decay of Berkelium-248 (²⁴⁸Bk) and Seaborgium-260 (²⁶⁰Sg) is 0.0292 h $k = M^{- n + 1} \cdot t^{- 1}$ ¹ and 0.173 ms $k = M^{- n + 1} \cdot t^{- 1}$ ¹, respectively. Which sample decays at a faster rate?