General Chemistry 2 Final - Part 1 of 4
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21. Nuclear Chemistry / Mass Defect / Problem 22
Determine the energy produced per mole of U-235 in the following fission reaction:
10n + 23592U → 14054Xe + 9438Sr + 2 10n
The atomic masses are given below:
mU-235 = 235.04392 amu
mXe-140 = 139.92164 amu
mSr-94 = 93.91535 amu
mn = 1.00866 amu
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