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Consider the galvanic cell shown below with a potential of 1.369 V at 25°C
Pb(s) | PbCl2(s) | Cl–(0.20 M) || Cr2O72–(0.20 M), Cr3+(0.20 M), H+(0.20 M) | Pt(s)
Determine the Ksp value for PbCl2(s).
Cr2O72–(aq) + 14 H+(aq) + 6 e– → 2 Cr3+(aq) + 7 H2O(l) E°red = 1.232 V
Pb2+(aq) + 2 e– → Pb(s) E°red = –0.126 V
For the given cell notation, write an overall cell reaction:
Mn(s) | Mn2+(aq) || Fe2+(aq) | Fe(s)
Draw the cell diagram, label which electrode is the anode and the cathode. Draw arrows to show the directions in which the ions and electrons flow.
Consider the following redox reaction:
2 NH4+(aq) + MnO4−(aq) → 2 MnO2(s) + N2(g) + 4 H2O(l)
Write a shorthand notation for this reaction. In your notation, you can use an inert metal if necessary.
For the given cell notation, write an overall cell reaction:
Ni(s) | Ni2+(aq) || Br2(l) | Br−(aq) | Pt(s)
Explain why we need an inert electrode at the cathode.
For the given electrochemical cell, cell potential is dependent on the copper concentration in the cathode half-cell.
Pt(s) | H2(g, 1.0 atm) | H+(aq, 1.0 M) || Cu+(aq, ? M) | Cu(s)
This cell has an Ecell of 0.34 V. Determine the [Cu+] of the solution.
For the given electrochemical cell, cell potential is dependent on the pH of the solution.
Pt(s) | H2(g, 1.0 atm) | H+(aq, ? M) || Ag+(aq, 1.0 M) | Ag(s)
This cell has an Ecell of 923 mV. Determine the pH of the solution.