give-the-balanced-equation-for-the-following-half-reactions-occurring-in-an-acid

Question

Give the balanced equation for the following half-reactions occurring in an acidic solution.

i. I₂(s) → I⁻(aq)

ii. Cu⁺(aq) → Cu(s)

iii. MnO₄⁻(aq) → Mn²⁺(aq)

iv. PbO₂(s) → Pb²⁺(aq)

Accepted Answer

i. I₂(s) + 2 e⁻ → 2 I⁻(aq)
ii. Cu⁺(aq) + e⁻ → Cu(s)
iii. MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)
iv. PbO₂(s) + 4 H⁺(aq) + 2 e⁻ → Pb²⁺(aq) + 2H₂O(l)

Answer

i. I₂(s) + 2 e⁻ → 2 I⁻(aq)
ii. Cu⁺(aq) + e⁻ → Cu(s)
iii. MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l) + 5 e⁻
iv. PbO₂(s) + 4 H⁺(aq) → Pb²⁺(aq) + 2H₂O(l) + 2 e⁻

Answer

i. I₂(s) → 2 I⁻(aq) + 2 e⁻
ii. Cu⁺(aq) → Cu(s) + e⁻
iii. MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l) + 5 e⁻
iv. PbO₂(s) + 4 H⁺(aq) → Pb²⁺(aq) + 2H₂O(l) + 2 e⁻

Answer

i. I₂(s) → 2 I⁻(aq) + 2 e⁻
ii. Cu⁺(aq) → Cu(s) + e⁻
iii. MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)
iv. PbO₂(s) + 4 H⁺(aq) + 2 e⁻ → Pb²⁺(aq) + 2H₂O(l)

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