using-the-thermodynamic-values-below-calculate-the-s-rxn-for-the-following-react

Question

Using the thermodynamic data below calculate the ΔS°_rxn for the following reaction and justify the change in entropy.

2 NaF(s) + Cl₂(g) → 2 NaCl(s) + F₂(g)

Accepted Answer

ΔS°_rxn = +21.7 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.

Answer

ΔS°_rxn = –21.7 J/mol; The change in entropy is small because the reaction involves solid species.

Answer

ΔS°_rxn = –72.8 J/mol; The change in entropy is small because the reaction involves solid species.

Answer

ΔS°_rxn = +72.8 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.

Answer

ΔS°_rxn = +21.7 J/mol; The change in entropy is small because the reaction involves solid species.

Answer

ΔS°_rxn = –72.8 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.