what-is-the-percent-ionization-of-a-0-20-m-acetic-acid-ch3cooh-ka-1-8x10-5-what-

Question

What is the percent ionization of a 0.20 M acetic acid (CH₃COOH, K_a = 1.8×10^–5)? What is the value of the percent ionization when 0.20 M HCl is added to the solution? Explain why the two values are different.

Accepted Answer

For 0.20 M CH₃COOH: % ionization = 0.949%
For 0.20 M CH₃COOH + 0.20 M HCl: % ionization = 9.00×10^–3%
The percent ionization decreases due to the presence of additional H3O⁺ in the solution (common ion effect).

Answer

For 0.20 M CH₃COOH: % ionization = 1.56%
For 0.20 M CH₃COOH + 0.20 M HCl: % ionization = 4.57
The percent ionization increases due to the presence of additional H3O⁺ in the solution (common ion effect).

Answer

For 0.20 M CH₃COOH: % ionization = 1.13%
For 0.20 M CH₃COOH + 0.20 M HCl: % ionization = 7.52×10^–3%
The percent ionization decreases due to the presence of additional H3O⁺ in the solution (common ion effect).

Answer

For 0.20 M CH₃COOH: % ionization = 4.50%
For 0.20 M CH₃COOH + 0.20 M HCl: % ionization = 9.00%
The percent ionization increases due to the presence of additional H₃O⁺ in the solution (common ion effect).

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What is the percent ionization of a 0.20 M acetic acid (CH₃COOH, K_a = 1.8×10^–5)? What is the value of the percent ionization when 0.20 M HCl is added to the solution? Explain why the two values are different.

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What is the percent ionization of a 0.20 M acetic acid (CH3COOH, Ka = 1.8×10–5)? What is the value of the percent ionization when 0.20 M HCl is added to the solution? Explain why the two values are different.

What is the percent ionization of a 0.20 M acetic acid (CH₃COOH, K_a = 1.8×10^–5)? What is the value of the percent ionization when 0.20 M HCl is added to the solution? Explain why the two values are different.