General Chemistry
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Using the thermodynamic data below calculate the ΔS°rxn for the following reaction and justify the change in entropy.
2 NaF(s) + Cl2(g) → 2 NaCl(s) + F2(g)
ΔS°rxn = –21.7 J/mol; The change in entropy is small because the reaction involves solid species.
ΔS°rxn = +21.7 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.
ΔS°rxn = –72.8 J/mol; The change in entropy is small because the reaction involves solid species.
ΔS°rxn = +72.8 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.
ΔS°rxn = +21.7 J/mol; The change in entropy is small because the reaction involves solid species.
ΔS°rxn = –72.8 J/mol; The change in entropy is small because there is no net change in moles of gas in the reaction.