General Chemistry
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Consider the isotope 201Hg. Provide the balanced nuclear equation when it undergoes positron emission.
80201Hg→ 79201Au+ +10e_{\text{80}}^{\text{201}}Hg\to\text{ }_{\text{79}}^{\text{201}}Au+\text{ }_{\text{+1}}^{\text{0}}e80201Hg→ 79201Au+ +10e
80201Hg→ 79200Au+ +10e_{\text{80}}^{\text{201}}Hg\to\text{ }_{\text{79}}^{\text{200}}Au+\text{ }_{\text{+1}}^{\text{0}}e80201Hg→ 79200Au+ +10e
80201Hg→ 81202Tl+ –10e_{\text{80}}^{\text{201}}Hg\to\text{ }_{\text{81}}^{\text{202}}Tl+\text{ }_{\text{–1}}^{\text{0}}e80201Hg→ 81202Tl+ –10e
80201Hg→ 81201Tl+ –10e_{\text{80}}^{\text{201}}Hg\to\text{ }_{\text{81}}^{\text{201}}Tl+\text{ }_{\text{–1}}^{\text{0}}e80201Hg→ 81201Tl+ –10e