8. Thermochemistry
Enthalpy of Formation
4PRACTICE PROBLEM
Acid spills are frequently neutralized using sodium carbonate or sodium hydrogen carbonate. The unbalanced equations that show the neutralization of benzoic acid are
HCOOH(l) + Na2CO3(s) → NaHCOO(aq) + CO2(g) + H2O(l)
HCOOH(l) + NaHCO3(s) → NaHCOO(aq) + CO2(g) + H2O(l)
Determine the amount of heat absorbed or released in kilojoules by the neutralization of 0.500 gallons of formic acid (density = 1.22 g/mL).
ΔH°f, NaHCOO(aq) = −293.3 kJ/mol
ΔH°f, HCOOH(l) = −425.0 kJ/mol
ΔH°f, Na2CO3 = −1130.7 kJ/mol
ΔH°f, NaHCO3 = −950.8 kJ/mol
ΔH°f, CO2(g) = −393.5 kJ/mol
ΔH°f, H2O(l) = −285.8 kJ/mol
Acid spills are frequently neutralized using sodium carbonate or sodium hydrogen carbonate. The unbalanced equations that show the neutralization of benzoic acid are
HCOOH(l) + Na2CO3(s) → NaHCOO(aq) + CO2(g) + H2O(l)
HCOOH(l) + NaHCO3(s) → NaHCOO(aq) + CO2(g) + H2O(l)
Determine the amount of heat absorbed or released in kilojoules by the neutralization of 0.500 gallons of formic acid (density = 1.22 g/mL).
ΔH°f, NaHCOO(aq) = −293.3 kJ/mol
ΔH°f, HCOOH(l) = −425.0 kJ/mol
ΔH°f, Na2CO3 = −1130.7 kJ/mol
ΔH°f, NaHCO3 = −950.8 kJ/mol
ΔH°f, CO2(g) = −393.5 kJ/mol
ΔH°f, H2O(l) = −285.8 kJ/mol