16. Chemical Equilibrium
Equilibrium Constant Calculations
17PRACTICE PROBLEM
At 27.0 °C, the aqueous reaction between CH3OH and HBr is as follows: CH3OH(aq) + HBr(aq) → CH3Br(aq) + H2O(l). What is the rate constant for the reverse reaction (kr) if the rate constant for the forward reaction (kf) and equilibrium constant (Kc) at 27.0 °C are, respectively, 1.67×10—4 M—1•s—1 and 1.20×102?
At 27.0 °C, the aqueous reaction between CH3OH and HBr is as follows: CH3OH(aq) + HBr(aq) → CH3Br(aq) + H2O(l). What is the rate constant for the reverse reaction (kr) if the rate constant for the forward reaction (kf) and equilibrium constant (Kc) at 27.0 °C are, respectively, 1.67×10—4 M—1•s—1 and 1.20×102?