General Chemistry
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Given the following data at 500 K:
CH4(g) + O2(g) ⇌ C(s) + 2 H2O(g); K1 = 7 x 1059
CO2(g) ⇌ C(s) + O2(g); K2 = 9 x 1047
Determine the value of the equilibrium constant at the same temperature for the reaction CH4(g) + 2 O2(g) ⇌ CO2(g) + 2 H2O(g).
Calculate the equilibrium constant for the reaction A2(g) + B2(g) + C2 (g) ⇌ 2 ABC(g) given the reactions below and their respective equilibrium constants.
The following equation below shows the reaction of hydrogen sulfate anion (HSO4-) with ammonia (NH3) to form sulfate (SO42-) and ammonium ions (NH4+).
HSO4-(aq) + NH3(aq) ⇌ SO42-(aq) + NH4+(aq)
The value of Ka for hydrogen sulfate anion (HSO4-) is 1.26 x 10-2 while the Kb value for ammonia (NH3) is 1.8 x 10-5.
Determine whether the value of Kc will be >1 or <1 for this reaction? Identify the direction which will be favored at equilibrium for this reaction.
At 789 K, the equilibria for the following reactions are
CuS(s) + H2(g) → Cu(s) + H2S(g) Kc = 78.9
CS2(g) + H2(g) → CS(g) + H2S(g) Kc = 0.289
Based on the given equilibria, what will be the Kc for CuS (s) + CS (g) → Cu (s) + CS2 (g)?
Calculate the equilibrium constant Kp for the following reaction at 373.15 K:
2 NO2(g) ⇌ N2(g) + 2 O2(g)
Use the following reactions and their Kc at the same temperature:
NO(g) + 1/2 O2(g) ⇌ NO2(g) Kc = 8.0×104
2 NO(g) ⇌ N2(g) + O2(g) Kc = 5.0×1024
The dissociation of hydrogen selenide (H2Se) takes place in two steps:
H2Se ⇌ H+ + HSe- K1 = 1.29×10-4
HSe- ⇌ H+ + Se2- K2 = 1.00×10-11Calculate the equilibrium constant for the following reaction:Se2- + 2H+ ⇌ H2Se
The following reaction is a vital step in the metabolism of glucose: glucose + ATP ⇌ glucose-6-phosphate + ADP
Determine the equilibrium constant for the above reaction using the related equilibrium constants:
glucose + Pi ⇌ glucose-6-phosphate, K = 3.114 × 10–3
ATP ⇌ ADP + Pi, K = 2.716 × 105