Fructose, C6H12O6, is the sweetest naturally occurring sugar and is found in many fruits and berries. Each carbon has four covalent bonds, each oxygen has two covalent bonds, each hydrogen has one covalent bond, and the atoms are connected in the sequence shown. Draw the complete struc-tural formula of fructose.

Question

Skeletal formula of fructose, C6H12O6, showing carbon, hydrogen, oxygen bonds.

Accepted Answer

Hello everyone in this video, we're given this structure right up here a saccharine. So there's an artificial sweetener that's about 550 times as sweet as sucrose. Each carbon oxygen, nitrogen atom has to follow this octet rule while hydrogen only needs to form one bond that fulfills its duet rule. The sequence of carbon atoms is shown below will provide the complete structural formula for this patron. All right. So we can see here that the structure is just missing hydrant items. If we add any of the carbon, nitrogen and oxygen atoms, we won't be able to fulfill the octet rule because we can add anything else to it. So we see that carbon usually likes or we know that carbon likes to have four different bonds or four bonds. It can either be single bonds, the bonds or triple bonds. As long as it has four different bonds connected to it. To fulfill its octet. Starting off with the six member bring over on the left side of the molecule. We can see maybe this one right here that it has 123 total bonds to form a double bond and one from the single bond we know that we have to add or hydrogen here because hydrogen only needs to have one bond or two lone pairs or two electrons not long pairs because of the duet rule. So it usually is a terminal atom. So same thing as for the rest of the six member ring on the left side at least that we have to add hydrogen to fill everything octet here. So hydrogen here here and here. Now getting towards the center of this molecule here, these do not need any hydrogen is because we can see here that we have 1234 bonds. These two carbons are identical. So if this one doesn't need it, this one does not either. But just to make sure we have 123 and four. Now you can see her for nitrogen, nitrogen also has sort of like trend that follows similar to carbon. So like I said, carbon does like to have four bonds. Nitrogen on the other hand, likes to have three bonds and one lone pair. The long hair has never drawn in this sort of structure, but it is there. But we do also realize that we only have two bonds. Again, hydrogen can be a terminal atom. So we can go ahead and just connect a hydrogen there. We can see now that we have three bonds and like I said, the lone pairs invisible now we have filled the nitrogen oxide as well. As for our oxygen's here, oxygen likes to have two bonds and it does have two lone pairs. Again, they're hidden. And all the oxygen. Or matter of fact, all of our elements now do have its octet being fulfilled. So my final answer then it's going to be this structure right over here with our terminal hydrogen is being included

Verified Solution

Key Concepts

Covalent Bonding

Structural Formula

Molecular Geometry