Here in this example question it states the formation of gaseous ammonia is displayed by the equation given below. Here we have one mole of nitrogen gas reacting with one mole of hydrogen gas to produce 2 moles of ammonia gas. What is the reaction quotient if the following amounts in moles of each component is placed in a 10 liter vessel?

All right, so here we have the moles of N₂, H₂, and NH₃ respectively. So remember we're going to set up an expression in the same way we would set up an expression for equilibrium constant K. But here it's going to be Q equals products over reactants. If we look, everything is in the gaseous state. There are no solids or liquids, so we're not going to ignore any of the compounds.

So here would be NH₃. Remember, your coefficient becomes your exponent or power, so this would be squared divided by N₂ times H₂. Remember, when it comes to these expressions, we typically use the units of molarity or atmospheres. Here they're giving us moles, and they're also giving us liters. With this information, we can figure out our molarity.

So you would divide each one of these moles by 10 liters, and when you do that you get our new molarities for each one. So here NH₃ will become 0.0529 molar. It'd still be squared divided by N₂, which is 0.0650, times H₂, which is 0.0330. When we punch that into our calculators, we'll get 1.3046 as our reaction quotient Q value.

If we look at the question, all these numbers have three significant figures, so I'm going to round this down to 1.30 as our final answer. So this will represent the value of our reaction quotient Q.