Here it says calculate the nuclear binding energy in mega electron volts per mole of beryllium 10. Here we're told the atomic mass of beryllium 10 is 10.0135347 AMU. All right, so step zero is. We'll repeat steps one to three of the previous topic to calculate the mass defect of the radioisotope, so beryllium 10. So beryllium has an atomic number 4. It has four protons, 4 electrons and 10 -, 4 six neutrons.
Here we would find out what the complete total mass of all of these subatomic particles are to help us determine our predicted mass. So here we multiply them by their masses in AMU. So we multiply them across and we add the mall together. That's going to give us our predicted mass. So our predicted massage equals 10.08324 AMU. Here they're giving us the atomic mass. The atomic mass is related to our nuclear mass, which is 10.0135347 AMU. Subtracting these two gives us our mass defect, which is M. The mass defect here would be 0.0697053 AMU.
All right, So now that we have that, what we would do next is we would have to convert AMU into kilograms. And here we have a conversion that one AMU is equal to 1.66×10-27 kilograms. All right. So here we're going to say one AMU is 1.66×10-27 kilograms. So when we do that, we would get 1.1571×10-28 kilograms. This is important to remember because remember 1 Joule is equal to kilograms times meter squared over second squared. That's why we need to convert AMU into kilograms.
At this point we'd say that our nuclear binding energy is equal to mass defect times speed of light squared. So plug in what we just found for mass defect times our speed of light squared. When we do that, that's going to give me 1.041×10-11 kg times meter squared over second squared or Joules. Remember, when we're using this formula for calculating nuclear binding energy, it is equal to 1 mole of that radioisotope. So this is joules per one mole.
Now in this question, I don't want Jules per mole, they want Mega Electron Volts per mole. So we'd use the other conversion factor that we have here, where we have one Mega Electron Volt equal to 1.60×10-13 Joules. Here, Joules would cancel out and we'd be left with Mega Electron Volts per mole. Here this would come out to be 65.087 Mega Electron Volts per mole O. This would be our final answer.
