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Ch.14 - Chemical Kinetics
Chapter 14, Problem 31

What is the rate of formation of C2H4 between 20 and 30 seconds for the reaction: C4H8(g) → 2 C2H4(g), given the tabulated data collected for the concentration of C4H8 as a function of time?

Verified step by step guidance
1
Identify the reaction: \( \text{C}_4\text{H}_8(g) \rightarrow 2 \text{C}_2\text{H}_4(g) \).
Understand that the rate of formation of \( \text{C}_2\text{H}_4 \) is related to the rate of disappearance of \( \text{C}_4\text{H}_8 \).
Use the rate expression: \( \text{Rate of formation of } \text{C}_2\text{H}_4 = -2 \times \frac{\Delta [\text{C}_4\text{H}_8]}{\Delta t} \).
Determine \( \Delta [\text{C}_4\text{H}_8] \) by finding the change in concentration of \( \text{C}_4\text{H}_8 \) between 20 and 30 seconds from the data.
Calculate \( \Delta t \) as the difference in time, which is 30 seconds - 20 seconds.