Draw the structure of the iron oxalate complex [Fe(C2O4)3]3-. Describe the coordination geometry, and identify any chelate rings. What are the coordination number and the oxidation number of the iron?

Video transcript

Hello, everyone. Today, we have the following problem sketch the structure and identify the coordinate co ordination geometry of the Cobalt complex. Distinguish the chelate rings of present, provide the coordinations and oxidation numbers of cobalt. So the first thing we want to do with this complex is identify the ligand. And so we see here that it has an EIN which represents this as an ethylene diamine. So if we draw out our ligand with the following structure, we have the ethylene diamine. So we will have our ethylene group followed by our two amine groups. That's where the dye portion comes from and the diamine. And then we see that we have a, that in these nitrogen atoms, there are two donor atoms each. And so this makes it a b dentate molecule. And we see that the, the charge here for this ligand is zero. So it's neutral. And so what you wanna do is you want to determine the co ordination at number and that can be determined by taking the three from the in and from the ethylene diamine, we multiply it by two from the two donor atoms each and we get six as a co-ordination number giving us the geometry of an octahedral structure. And so, furthermore, we want to determine the oxidation number. So how do we do that? Well, we take the overall charge so it's equal to the overall charge that is equal to one times the oxidation number of cobalt. So oxidation state or number of cobalt plus three times the oxidation state of our ethylene diamine. And so the overall charge of this molecule is positive three. So we have positive three is equal to one times the oxidation state of cobalt will have Cobalt because that's the because that is the variable that we are trying to find. And then we have plus three times the oxidation state of our ethylene diamine, it is neutral. So it has a zero charge. And thus, that gives us an oxidation state for Cobalt equaling positive three. So how we want to draw this is we want to start with the metal in the center and it has an octahedral confirmation. So first, we draw one ball line going directly up, one going down. And then we have our octahedral confirmation where we have our two bonds on a wedge and two on a dash connects to the, the ring connects to the metal. And so since we said that this is a bent ta, this means that the structure will have three chelate rings. And so now, after drawing the base of the structure, we have to add our ethylene diamine. And so how we would do this is we will essentially connect our nitrogen atoms to our bond. And then we connect the rest and we are essentially going to do this for the rest of the other lids such that we have the following. And thus, this is our structure as well as our oxidation number of Cobalts as well as its coordinator number. And with that, we have solved the problem overall, I hope this helped. And until next time.