Here it says what is the reaction quotient for the following redox reaction with the given concentrations. Alright, so here we have lead to ion reacting with two moles of potassium solid to produce one mole of lent solid +2 moles of potassium ion. Here we're going to say that the concentration of lead to ion and potassium ion are given as these molarities.

Now remember that your reaction quotient Q can be solved by setting up its expression and Q equals products overreacts. Now remember with this expression we ignore solids and liquids, so the solids we're going to ignore. So it basically becomes the concentration of K positive. And remember, because there's a 2 here, that becomes our exponent, so K positive squared divided by PB2 plus.

Here we plug in the values for each one. So potassium ion it's 0.0015, which will be squared divided by 0.0880. When we punch this into our calculators, we get 2.6×10-5. So this represents the value for our reaction quotient Q.