Calculate the solubility of silver chloride in a solution that is 0.100 M in NH3.

Video transcript

Hello. In this problem we are asked to determine the reliability of copper to carbonate in a 0.350 molar solution of ethylene dimming, abbreviated as the n. Using the following data were given the formation constant for complex sign and the solid ability product constant for copper to carbonate. We'll begin by writing then the reactions that describe the formation of the complex line and then the solid ability of copper to carbonate. So forming our complex iron, we have copper two plus ions reacting with ethylene diamond to form our complex sign, says the equilibrium constant then of our formation constant and then we have copper to carbonate and equilibrium with its ions. And the equilibrium constant then is the scalability product constant. So we'll come up with an overall reaction by combining these two. We see that we have copper rounds on both reactant on the product side. So those will cancel. But then left with copper to carbonate, reacting with ethylene diamond from our complex iron and carbonate. Now that we have our overall reaction, we'll write our ice table. So we have initial change and equilibrium we're going to ignore the pure solid since it won't appear in our equilibrium constant expression, we initially have a concentration of 0.350 Mueller of ethylene diamond. None of the complex sign and none of the carbonate are changes minus two X. And then plus X plus X. Will combine the initial and the change to get our equilibrium our equilibrium constant then for the overall reaction is equal to formation constant times scalability product constant. Since the overall reaction is the sum of these two reactions. This then works out to one Times 10 to the Times 2.40 times 10 -10. So our equilibrium constant for the overall reaction then is 2. Times 10 to the 10 writing the expression. Then for our overall equilibrium constantly have the concentration of our products all over. The concentration of our reactant, Kathleen dining squared. Again, Pure solid does not appear in our equilibrium constant expression, looking at the ice table, then the complex ion and carbonate both X. So that works out to X times X, which is X squared divided by 0.350 minus two X. And that's squared. That's equal to than 2.40 Times 10 to the 10. You can simplify this by taking the square root of both sides. Thank You. X divided by .350 -2 x. It's equal to the square root of 2.4, 0 Times 10 to the 10, which works out to 1.54, 9 times 10 to the five. And then we'll multiply both sides by 0.350 -2 x. And simplify this further. And then we'll collect everything to the left hand side that has our variable X. And then solve for X. Which works out to 0.175 from our ice table. We know this is then the concentration of our carbonate anna. And then for every one mole carbonate, They have one mole of copper to carbonate. So This works out then 2. Mueller, which again is the concentration and of to carbonate this corresponds. And to answer a thanks for watching. Hope this helps.