Provide a complete reaction of benzene Friedel Crafts alkylation with 2-bromo-2-methylpropane and name the product.

• A.
• B.
• C.
• D.

Answer: (B)

Verified step by step guidance

1. Identify the reactants: Benzene (C₆H₆) and 2-bromo-2-methylpropane ((CH₃)₃CBr).
2. Understand the role of the catalyst: Friedel-Crafts alkylation requires a Lewis acid catalyst, commonly aluminum chloride (AlCl₃), to facilitate the reaction.
3. Generate the carbocation: The Lewis acid (AlCl₃) interacts with the bromine in 2-bromo-2-methylpropane, forming a carbocation ((CH₃)₃C⁺) by removing the bromide ion.
4. Electrophilic attack: The benzene ring, acting as a nucleophile, attacks the carbocation, forming a sigma complex (arenium ion) where the alkyl group is temporarily bonded to the benzene ring.
5. Reform the aromatic system: The sigma complex loses a proton (H⁺), restoring the aromaticity of the benzene ring and forming the final product, tert-butylbenzene.