The accompanying graph illustrates the decay of ⁸⁸₄₂Mo, which decays via positron emission. (c) What fraction of the original sample of ⁸⁸₄₂Mo remains after 12 min? [Section 21.4]

Video transcript

Hello. Everyone in this video. We're given this illustration right over here and this displays the decay of 110 s. And by electron capture. So in this question we need to find the fraction of the initial amount of this here remaining after 12 hours. So using this graph we can estimate the mass of the 110 S. N. In the graph at 12 hours we see at 12 is going to be right over here. So we just need to draw online and we can just draw a line to the Y axis. And we can see here that we have approximately maybe 1.25 for the mass of the 110 50 S. N. Let's actually write this out um down below for more space here. Alright, so again we said that the mass or the estimated mass of the 50 S. N is approximately 1.25 g from the graph. So then the fraction is equal to The amount of 110 s and sub team divided by 110 50 S and initial or not. So putting in the numerical values we have 1.3 g was round at the 1.25 divided by 10 g. And this gives us a fraction to be equal to 0.13. So 0.13 is going to be my final answer for this problem