Here it says consider the reaction. We have one mole of nitrogen gas reacting with one mole of oxygen gas and one mole of bromine gas to produce 2 moles of Nobr gas. Here we'll told the enthalpy value was -32.5 kilojoules. So here we're saying that the enthalpy is negative, so it's exothermic, which means he does released. So heat would have to be a product all right.
So now the phone changes will shift equilibrium to the left except all right. So removing N2, if you remove some reactor, you have to replenish the reactor you lost, so you would have to move in the left direction to remake it. So this does move to the left, increasing the partial pressure of NOBr. So when we say increase the partial pressure of a gas, that just means adding more moles of that gas. Because remember, the quantity of a gas is directly connected to its partial pressure. The more of it in it that we have, the higher the partial pressure.
So in essence, this part C is saying that I'm increasing the amount of product to get rid of it. I'd have to move to the left again to get rid of it. So this is out. Increase the pressure in container. Now this is different. We're not increasing the partial purchase of any gases. We're increasing the overall pressure of the container. Increasing pressure is equivalent to decreasing volume in either instance. All that means that we're shifting to the side width. Less moles gas on this side here, see this side here, we have 3 moles of gas. On this side here, we have two moles of gas. So again, we're shifting to the side that has less moles of gas. South, we're shifting to the right.
So right now this is an example of a ship that's not to the left. Next, adding some NOBr is equivalent to option C, where we're increasing the partial pressure of NOBr. They're both saying the same thing. We shift to the right, to the left to get rid of it, decreasing the temperature. If we're decreasing the temperature, we have to shift towards the heat. The heat is on the product side, so we'd be shifting towards the right. So this is also an example of the equilibrium shifting to the right and to the left, sorry, to the right to the right.
Now lastly, F decrease the container volume, which is the same thing as saying E word, decreasing container volume, which is the same thing as increasing pressure of the container. So we're going to shift to the side width less moles of gas. So this would also shift to the right. So in this one, EDNF would all shift to the right, so they would be the answer. They're the ones that are not shifting to the left. So again, DE and F are our final answers.