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Ch.1 - Introduction: Matter, Energy, and Measurement

Ch.2 - Atoms, Molecules, and Ions

Ch.3 - Chemical Reactions and Reaction Stoichiometry

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BONUS: Mathematical Operations and Functions

Ch.4 - Reactions in Aqueous Solution

Ch.5 - Thermochemistry

Ch.6 - Electronic Structure of Atoms

Ch.7 - Periodic Properties of the Elements

Ch.8 - Basic Concepts of Chemical Bonding

Ch.9 - Molecular Geometry and Bonding Theories

Ch.10 - Gases

Ch.11 - Liquids and Intermolecular Forces

Ch.12 - Solids and Modern Materials

Ch.13 - Properties of Solutions

Ch.14 - Chemical Kinetics

Ch.15 - Chemical Equilibrium

Ch.16 - Acid-Base Equilibria

Ch.17 - Additional Aspects of Aqueous Equilibria

Ch.18 - Chemistry of the Environment

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Brown - Chemistry:The Central Science 14th Edition

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Law of Conservation of Mass

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Chapter 15, Problem 76c

A sample of nitrosyl bromide (NOBr) decomposes according to the equation 2 NOBr(𝑔) ⇌ 2 NO(𝑔) + Br₂(𝑔) An equilibrium mixture in a 5.00-L vessel at 100°C contains 3.22 g of NOBr, 3.08 g of NO, and 4.19 g of Br₂. (c) What was the mass of the original sample of NOBr?

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Chapter 15, Problem 76c

A sample of nitrosyl bromide (NOBr) decomposes according to the equation 2 NOBr(𝑔) ⇌ 2 NO(𝑔) + Br2(𝑔) An equilibrium mixture in a 5.00-L vessel at 100°C contains 3.22 g of NOBr, 3.08 g of NO, and 4.19 g of Br2. (c) What was the mass of the original sample of NOBr?

A sample of nitrosyl bromide (NOBr) decomposes according to the equation 2 NOBr(𝑔) ⇌ 2 NO(𝑔) + Br₂(𝑔) An equilibrium mixture in a 5.00-L vessel at 100°C contains 3.22 g of NOBr, 3.08 g of NO, and 4.19 g of Br₂. (c) What was the mass of the original sample of NOBr?