Here it says write the condensed electron configuration of the following ion. So here we have to do it for the silver ion. Its atomic number is 47, neutral silver if we look at the periodic table would look like it's initially Krypton 5 S2 4 D9. But remember it's one of the elements that exists under exception one. We would take an electron from an S orbital and promote it to the D. So the real electron configuration of neutral silver would be Krypton 5 S1 4 D10.
So we're looking at this as the real electron configuration of neutral silver. Now plus one means we've lost one electron which is going to come from the highest shell number. Here this one electron is in the 5th shell and these ten are in the fourth shell. The one electron we need to lose would come from the 5th shell.
So here it's electron. Condensed electron configuration would be Krypton 4 D10 and the way it would look is it would be Krypton. Our five is gone now so that orbital would not be filled in. These five would represent our 4D orbitals and be up, up, up, up, up and then come back, around, down, down, down, down, down. So here we have our condensed electron configuration and our electron orbital diagram.