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Ch.1 - Chemical Tools: Experimentation & Measurement

Chapter 1, Problem 60

Sodium chloride has a melting point of 1074 K and a boil-ing point of 1686 K. Convert these temperatures to degrees Celsius and to degrees Fahrenheit.

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Welcome back, everyone. We need to express with correct number of sick. Fix the boiling 0.5 28 Kelvin and melting 280.3 71 Kelvin of aluminum bromide in degrees Celsius and degrees Fahrenheit. So let's begin with our boiling point of aluminum bromide. We would first calculate it in degrees Celsius by recalling that we would take the Kelvin temperature minus 2 73.15 to get our Celsius boiling point. And so plugging in our given Kelvin temperature of 528 Kelvin subtracted from 2 73.15. We want to recognize that our main operation is subtraction. And so for our final answer, we want the least number of decimal places. So when we take the difference, we have a result equal to 254.85. Now note that in 528 Kelvin, we have zero decimal places. Sorry, I'll just say zero decimal place at Shorthand here. And in to 73.15, we have a total of two decimal places. So we're going to go with the zero decimal place option as our final answer. Since our main operation is subtraction. And so we would round this answer to exactly 255 degrees Celsius with zero decimal places. So this would be our first answer as our boiling point in degrees Celsius for aluminum bromide. Now moving on to this boiling point in Fahrenheit recall that we can calculate it by taking 1.8 multiplied by our calculated Celsius temperature added to and sorry, this is added to 32. Now, we want to recall that whenever our final operation, whatever our final operation is, in this case, our final operation is going to be addition, we would also want our answer to be the least number of decimal places. And so in this case, we have zero decimal places for the number which we're adding and we have zero decimal places in our calculated Celsius temperature and one decimal place in our value 1.8. So plugging in what we know we have 1.8 times are Celsius temperature to 55 added to 32. Note that we would multiply first and then plus 32 is our final operation. So our final answer will be the least number of decimal places being zero. And we would result in a final boiling point in Fahrenheit as 491 degrees Fahrenheit with zero decimal places, meaning we know that this is the correct final answer. Now, moving on to our melting point of aluminum bromide, we would begin by calculating it in Celsius. So we would take the given Kelvin melting point as 371. Kelvin, which is subtracted from 2 73.15. Note, we have zero decimal places in 3 71. Kelvin and two decimal places in To 73.15. And our main operation is subtraction. So we would have our answer be the least number of decimal places. So from this difference, we get a value of 97.85 because our least number of decimal places is zero. We want our final answer to be rounded to about exactly, 90, sorry exactly 98 degrees Celsius. This would be our first, we're sorry, our second answer as are melting point in degrees Celsius. Now we want to calculate our melting point in degrees Fahrenheit. So utilizing the formula from before, we have 1.8 times are calculated Celsius temperature plus plugging in what we know, we have 1.8 times 98 for our Celsius temperature plus 32. Our final operation is addition of 32. And so we want our answer to be the least number of decimal places again. So in this case, we have zero decimal places in 32 as well as zero in our Celsius temperature, we have one decimal place in 1.8. We're going to go with zero decimal places because that's the least. And so simplifying this we would result in a value equal to 208 F, which has zero decimal places, which is what we want. So this would be our second answer for the melting point of aluminum bromide in degrees Fahrenheit. So everything highlighted in yellow represents our four final answers corresponding to choice D in the multiple choice as our melting point and boiling point of aluminum bromide in both Celsius and Fahrenheit degrees. I hope everything I explained was clear. If you have any questions, please leave them down below and I'll see everyone in the next practice video.
Related Practice
Textbook Question

Suppose you were dissatisfied with both Celsius and Fahrenheit units and wanted to design your own temperature scale based on ethyl alcohol (ethanol). On the Celsius scale, ethanol has a melting point of -117.3 °C and a boiling point of 78.5 °C, but on your new scale calibrated in units of degrees ethanol, °E, you define ethanol to melt at 0 °E and boil at 200 °E. (c) What are the melting and boiling points of water on the ethanol scale?

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Textbook Question

Suppose you were dissatisfied with both Celsius and Fahrenheit units and wanted to design your own temperature scale based on ethyl alcohol (ethanol). On the Celsius scale, ethanol has a melting point of -117.3 °C and a boiling point of 78.5 °C, but on your new scale calibrated in units of degrees ethanol, °E, you define ethanol to melt at 0 °E and boil at 200 °E. (d) What is normal human body temperature (98.6 °F) on the ethanol scale?

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Textbook Question

Suppose you were dissatisfied with both Celsius and Fahrenheit units and wanted to design your own temperature scale based on ethyl alcohol (ethanol). On the Celsius scale, ethanol has a melting point of -117.3 °C and a boiling point of 78.5 °C, but on your new scale calibrated in units of degrees ethanol, °E, you define ethanol to melt at 0 °E and boil at 200 °E. (e) If the outside thermometer reads 130 °E, how would you dress to go out?

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