Which of the molecules below will be polar? CS₂, BF...

Question

Which of the molecules below will be polar? CS₂, BF₃, SO₂, CH₃Br

Accepted Answer

Hello everyone in this question we're asking all the lewis structures for the following compounds. And answer the questions below. We have s. f. four. We have six valence electrons for sulfur Plus seven Valence Electrons for Fleury. And that's fourth floor range. And that'll give us 34. And for the lower structure we're gonna have sulfur in the center. Does it was less electro night in the flooring. We're gonna have four flooring coming off of it. We have 2468 10 12 14, 16, 18, 20 22 24 26 30 32 34. We're gonna have a lone pair of round sulfur because it can have an expanded octet. And we have one two three four five electron groups around Sulfur. And we have one lone pair. So we're gonna have Children or by poor and middle for the electron geometry. And they're gonna have seesaw for the molecular geometry. And that's going to give us bond angles of 120 degrees and degrees. And from br F five We have seven valence electrons for bro mean Plus seven for flooring Times five. Because we have five flooring And this will give us valence electrons. We're gonna bring me in the center and far flooring coming off of it And we have (246) 810 12 14 18, 20 22 24 26 30 32 34 36 40 42. We have six electron groups around bro mean. So that's gonna give us Octa hydra for the electron geometry and a molecular geometry it's going to be square, you're in middle. So this is gonna give us a bond angle of less than 90°. They were gonna have PCL five, We're gonna have five valence electrons Plus seven valence electrons times five. And this gives us 40 electrons. And for the structure we're gonna have phosphorus in the center, The five chlorine coming off of it. So I have 2468, 10, 12 14, 16, 18, 20 22 24 26, 30 32 34 36 40. We have five electron groups around phosphorus and we have no lone pairs. So we're gonna have triggered i pyramidal for the electron geometry and the molecular geometry. And this gives us bond angles of 120° and 90 degrees. They're gonna have X E F two. We're gonna have eight valence electrons plus seven times two. And this will give us 22. We're gonna have X in the center and to flooring coming off of it And we have 24 six, eight, 10, 12, 14, 16, 18, 20 22. So we have five electron groups around xenon. And this will give us triggered by pyramidal for the electron geometry and linear For the molecular geometry since we have three long pairs. So our bond angle is going to be 180°. If a Kr cl four We have eight valence electrons Plus seven Valence Electrons Times four. And this will give us 36 valence electrons. We're gonna have krypton in the center before chlorine coming off of it. So we have 2468, 10, 12, 14, 16, 18, 20 22 24 26, 30 32 34 36. We have six electron groups around Krypton. So that's going to be octahedron for the electron geometry. And since we have two long pairs, the molecular geometry is going to be square planner And this will give us a bond angle of 90°. And if we look at a were asked which of the compounds has at least one bond angle measuring around 120°. This is going to be SF four, N PCL five for B. You have to identify any compounds which may have the sp three D two hybridization. So this means we're looking at six electron groups around the central atom. So there's going to be BRF five in KR Cl four and then we need to identify any compounds with the square planter geometry. This is going to be KR cl four And they were asked which of the following compounds are polar. So if you look at the first one, this is gonna be polar because we have that pole moments due to the lone pair For the 2nd 1. This is also going to be polar because of the long pair, we have dipole moments. For PCL five, it's going to be non polar because we have all the same atoms surrounding the central atom. We have no lone pairs. So we have no dipole moments. And for X. Cf two, this is going to be non polar as well, since we have three lone pairs and they're arranged in a certain way, they're going to cancel out. So we're gonna be left with no dipole moments. And or Kr cl four, we have two long pairs. But since they're arranged in a certain way, the dipole moments are going to cancel out that it's gonna be non polar as well. So for the two polar compounds We're gonna get s. f. four and BR F. Five. Thanks for watching my video and I hope it was helpful.

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