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Ch.7 - Quantum-Mechanical Model of the Atom
Chapter 7, Problem 51

What is the de Broglie wavelength of an electron traveling at 1.35 x 10^5 m/s?

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1
Identify the formula for the de Broglie wavelength: \( \lambda = \frac{h}{mv} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant (6.626 x 10^{-34} \text{ m}^2 \text{ kg/s}), \( m \) is the mass of the electron (9.109 x 10^{-31} \text{ kg}), and \( v \) is the velocity of the electron.
Substitute the given velocity \( v = 1.35 \times 10^5 \text{ m/s} \) into the formula.
Substitute the known values for Planck's constant \( h = 6.626 \times 10^{-34} \text{ m}^2 \text{ kg/s} \) and the mass of the electron \( m = 9.109 \times 10^{-31} \text{ kg} \) into the formula.
Calculate the de Broglie wavelength by performing the division \( \lambda = \frac{6.626 \times 10^{-34}}{9.109 \times 10^{-31} \times 1.35 \times 10^5} \).
Simplify the expression to find the de Broglie wavelength \( \lambda \).
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