Provide a condensed electron configuration for vanadium 3 ion. So what we should do first is write the electron configuration of neutral vanadium. So Vanadium atom, if we look at the periodic table, would be Argon 4S23D3.
Now vanadium 3 ion, we've lost three electrons. Remember the first electrons come from the highest shell number, which would be electrons from the 4S orbitals because they're in the fourth shell. So we lose 2 from there. So those are gone now and we have to lose one additional electron because we need to lose 3. It would have to come from 3D.
So we have left at the end is argon 3D2. This would be the condensed electron configuration of the vanadium 3 ion.