What fraction of the film is left after 10 s, assuming the same initial coverage as in part a, given that the evaporation of a 120-nm film of n-pentane from a single crystal of aluminum oxide is zero order with a rate constant of 1.92 * 10^13 molecules/cm^2 * s at 120 K?

Verified step by step guidance

1. Identify that the problem involves zero-order kinetics, where the rate of reaction is constant and does not depend on the concentration of the reactant.
2. Use the zero-order rate equation: \[ [A] = [A]_0 - kt \] where \([A]\) is the concentration at time \(t\), \([A]_0\) is the initial concentration, \(k\) is the rate constant, and \(t\) is the time.
3. Determine the initial concentration \([A]_0\) in terms of molecules/cm². Since the problem states the initial coverage is the same as in part a, use that initial concentration value.
4. Substitute the given rate constant \(k = 1.92 \times 10^{13}\) molecules/cm²·s and the time \(t = 10\) s into the zero-order rate equation.
5. Calculate the concentration \([A]\) at \(t = 10\) s and then find the fraction of the film remaining by dividing \([A]\) by \([A]_0\).