The reduction of iron (III) oxide creates the following reaction:
Fe2O3 (s) + 3 H2 (g) → 2 Fe (s) + 3 H2O (g)
If the above reaction only went to 75% completion, how many moles of Fe2O3 were require to produce 0.850 moles of Fe?
34.4 g
53.0 g
44.7 g
14.5 g
Master Percent Yield in Reactions with a bite sized video explanation from Jules Bruno
Start learning