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Ch.18 - Chemistry of the Environment
Chapter 18, Problem 19a

(a) Distinguish between photodissociation and photoionization.

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Understand the concept of photodissociation: Photodissociation is a process where a molecule absorbs a photon and breaks into smaller fragments. This typically involves the breaking of chemical bonds within the molecule due to the energy provided by the absorbed light.
Understand the concept of photoionization: Photoionization occurs when a molecule or atom absorbs a photon with enough energy to eject an electron, resulting in the formation of a positively charged ion.
Compare the energy requirements: Photodissociation generally requires less energy compared to photoionization, as breaking a bond often requires less energy than removing an electron from an atom or molecule.
Identify the outcomes: In photodissociation, the outcome is the formation of smaller molecular fragments, whereas in photoionization, the outcome is the formation of ions due to the loss of electrons.
Consider the applications and implications: Photodissociation is important in atmospheric chemistry and the breakdown of pollutants, while photoionization is crucial in processes like mass spectrometry and the study of ionization energies.

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