Consider the reaction: 2 NO(g) + O2(g) → 2 NO2(g) Estimate ΔG° for this reaction at each temperature and predict whether or not the reaction is spontaneous. (Assume that ΔH° and ΔS° do not change too much within the given temperature range.) b. 715 K
Ch.18 - Free Energy and Thermodynamics
Chapter 18, Problem 68
Calculate ΔG°rxn for the reaction: CaCO3(s) → CaO(s) + CO2(g). Use the following reactions and given ΔG°rxn values: Ca(s) + CO2(g) + 1/2 O2(g) → CaCO3(s) ΔG°rxn = -734.4 kJ, 2 Ca(s) + O2(g) → 2 CaO(s) ΔG°rxn = -1206.6 kJ.
Verified step by step guidance
1
Identify the target reaction: CaCO3(s) → CaO(s) + CO2(g).
Recognize that you need to manipulate the given reactions to derive the target reaction.
Reverse the first given reaction: CaCO3(s) → Ca(s) + CO2(g) + 1/2 O2(g), which changes the sign of ΔG°rxn to +734.4 kJ.
Divide the second given reaction by 2 to match the stoichiometry of the target reaction: Ca(s) + 1/2 O2(g) → CaO(s), which changes ΔG°rxn to -603.3 kJ.
Add the modified reactions together to cancel out intermediate species and obtain the target reaction, then sum the ΔG°rxn values to find ΔG°rxn for the target reaction.
Related Practice
Textbook Question
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Open Question
Consider the reaction: CaCO3(s) → CaO(s) + CO2(g). Estimate ΔG° for this reaction at each temperature and predict whether or not the reaction is spontaneous. (Assume that ΔH° and ΔS° do not change too much within the given temperature range.) a. 298 K b. 1055 K c. 1455 K.
Textbook Question
Determine ΔG° for the reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) Use the following reactions with known ΔG°rxn values:
2 Fe(s) + 3/2 O2(g) → Fe2O3(s) ΔG°rxn = -742.2 kJ
CO(g) + 12 O2( g) → CO2(g) ΔG°rxn = -257.2 kJ
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Open Question
Consider the sublimation of iodine at 25.0 °C: I2(s) → I2(g). a. Find ΔG°rxn at 25.0 °C.
Textbook Question
Consider the sublimation of iodine at 25.0 °C : I2(s) → I2(g) b. Find ΔG°rxn at 25.0 °C under the following nonstandard conditions: i. PI2 = 1.00 mmHg ii. PI2 = 0.100 mmHg
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Textbook Question
Consider the sublimation of iodine at 25.0 °C : I2(s) → I2(g) c. Explain why iodine spontaneously sublimes in open air at 25.0 °C
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