Skip to main content
Ch.6 - Thermochemistry
Chapter 6, Problem 118

A pure gold ring and a pure silver ring have a total mass of 14.9 g. The two rings are heated to 62.0 °C and dropped into 15.0 mL of water at 23.5 °C. When equilibrium is reached, the temperature of the water is 25.0 °C. What is the mass of each ring? (Assume a density of 0.998 g/mL for water.)

Verified step by step guidance
1
Identify the specific heat capacities of gold and silver, which are approximately 0.129 J/g°C and 0.235 J/g°C, respectively.
Use the formula for heat transfer: \( q = mc\Delta T \), where \( q \) is the heat absorbed or released, \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature.
Calculate the heat gained by the water using its mass (15.0 mL \( \times \) 0.998 g/mL) and its temperature change (25.0 °C - 23.5 °C).
Set up the equation for heat lost by the rings: \( q_{gold} + q_{silver} = -q_{water} \), where the negative sign indicates that the rings lose heat while the water gains it.
Use the total mass of the rings (14.9 g) and solve the system of equations to find the individual masses of the gold and silver rings.