Complete the following hydrohalogenation reaction. So here we have a cyclopentene reacting with hydrobromic acid. Here we're going to say we're going to break the double bond and both of these double bonded carbons are symmetrical.
So the H could go to either one and the BR could go to the other. Here I decide to add the hydrogen here and then the bromine would go here. In the process we've just created an alkyl halid.
Here we've created Bromo Cyclo Pentane as our final product.