Calculate the molarity of each solution. a. 0.38 mol of LiNO₃ in 6.14 L of solution b. 72.8 g C₂H₆O in 2.34 L of solution c. 12.87 mg KI in 112.4 mL of solution

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1. <insert step 1> Identify the formula for molarity: Molarity (M) = \( \frac{\text{moles of solute}}{\text{liters of solution}} \).
2. <insert step 2> For part (a), use the given moles of LiNO_3 and volume of solution to calculate molarity: \( M = \frac{0.38 \text{ mol}}{6.14 \text{ L}} \).
3. <insert step 3> For part (b), first convert the mass of C_2H_6O to moles using its molar mass (46.08 g/mol for ethanol), then calculate molarity: \( \text{moles} = \frac{72.8 \text{ g}}{46.08 \text{ g/mol}} \) and \( M = \frac{\text{moles}}{2.34 \text{ L}} \).
4. <insert step 4> For part (c), convert the mass of KI from mg to g (1 mg = 0.001 g), then to moles using its molar mass (166.00 g/mol for KI), and convert the volume from mL to L (1 mL = 0.001 L), then calculate molarity: \( \text{moles} = \frac{12.87 \text{ mg} \times 0.001 \text{ g/mg}}{166.00 \text{ g/mol}} \) and \( M = \frac{\text{moles}}{0.1124 \text{ L}} \).
5. <insert step 5> Ensure all units are consistent and calculations are correct to find the molarity for each solution.>