Determine the alkyl halid formed in the following reaction. So here we're starting out with our alcohol and this would be 1 propanol. We're going to react with hydrobromic acid.

Remember hydrobromic acid will convert the OH group into ABR. So now it becomes CH3CH2CH2Br. We go from 1 propanol to 1 bromo propane, so here we've gone from an alcohol to an alkyl halid and this would be our final answer.