Table of contents

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1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

11. Bonding & Molecular Structure

Resonance Structures

General Chemistry

11. Bonding & Molecular Structure

Resonance Structures

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Multiple Choice

Determine the average charge of the oxygen atoms within the chlorite ion, ClO₂^–.

+1/2

-1/2

-1

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Verified step by step guidance

Identify the overall charge of the chlorite ion, which is ClO₂⁻. This means the total charge of the ion is -1.

Recognize that the chlorite ion consists of one chlorine atom and two oxygen atoms.

Assign oxidation states based on common rules: typically, oxygen has an oxidation state of -2, and the sum of oxidation states in a polyatomic ion equals the ion's charge.

Let the oxidation state of chlorine be x. Set up the equation: x + 2(-2) = -1, where -2 is the oxidation state of each oxygen atom.

Solve for x to find the oxidation state of chlorine, then calculate the average charge of the oxygen atoms by considering the total charge and the oxidation state of chlorine.