Skip to main content
Ch.14 - Chemical Kinetics

Chapter 14, Problem 112c

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:

Step 1: (CH3)3AuPH3 k1 k -1 (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au k2 C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 ¡k3 1(CH3)AuPH3 (fast)

(c) What is the molecularity of each of the elementary steps?

Verified Solution
Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
358
views
Was this helpful?