Here it says determine the product formed in the following reaction. We have two moles of nitrogen solid reacting with three moles of diatomic fluorine. We know that we're reacting 2 moles of our group 5/8 element with three moles of diatomic halogen. The end result should be a Tri Halid, so we should create NF3.
We still have to balance this. We have two nitrogens on this side but only one here, so I put a 2 here. Doing that would also balance out my fluorines because two and three gives me 6 fluorines on the product side and we already have 6 fluorines on the reactant side.
So this would be represent the formation of nitrogen Tri fluoride or trihalid that have been formed from the reaction of two moles of our group 5A element with three moles of our diatomic halogen.