Here it says the heat capacity of a bomb calorimeter was determined by burning 12.13 grams of ethane. We're told the heat of combustion equals 1560 kilojoules per mole in the bomb. If the temperature changed by 15.2�C, we have to determine the heat capacity of the bomb calorimeter.

All right, so remember that is enthalpy of combustion equals positive Q of object, the one that absorb the heat plus Q of the calorimeter. Here we're going to convert the heat of combustion from kilojoules to Joules, which is customary with these types of questions. So remember one KJ is 10 to the three joules, so that is joules uh mole. Remember, enthalpy of combustion is exothermic, so this is a negative sign here.

Now we have one 2.3 grams of ethane. Ethane's formula is C₂H₆, and here if we convert it into moles, all right, so we have two carbons, which is two 4.02g for the two carbons. And then we have 6 hydrogens each one is 1.008, so their combined mass is 6.048. So this comes from the two carbons and the six hydrogens of ethane. When we add that up together, the mass is 30.068g per one mole.

Take that mole. We're going to plug it in here for the cue of the object, so the map. The moles are 0.4034 moles times its specific heat capacity, which when you look it up is approximately 52.63 joules. Over moles times degrees Celsius, the temperature changed by one 5.2�C, so that's our Delta T. We're looking for the heat capacity of the calorimeter times the change in temperature again, which is still one 5.2�C.

Moles cancel out, Degrees Celsius cancel out. When I multiply those together, I'm going to get 322.710 Joules plus my heat capacity again times the change in temperature. Subtract out what we have here. When we do that, we're going to get 1559677.29 equals heat capacity times the change in temperature. Divide out one 5.2�C and when we do that we're going to get the heat capacity equal to 1.03 * 10⁵ joules over degrees Celsius. So that would represent the heat capacity of the bomb Cal. Remember within this given question.