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Ch.4 - Chemical Quantities & Aqueous Reactions
Chapter 4, Problem 45

For the reaction shown, calculate the theoretical yield of product (in grams) for each initial amount of reactants. 2 Al(s) + 3 Cl2(g) → 2 AlCl3(s) a. 2.0 g Al, 2.0 g Cl2 b. 7.5 g Al, 24.8 g Cl2

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<Step 1: Determine the molar masses of the reactants and product. Calculate the molar mass of Al, Cl2, and AlCl3 using the periodic table.>
<Step 2: Convert the mass of each reactant to moles. Use the formula: moles = mass (g) / molar mass (g/mol) for both Al and Cl2.>
<Step 3: Identify the limiting reactant. Use the stoichiometry of the balanced equation to determine which reactant will be consumed first. Compare the mole ratio of Al to Cl2 from the balanced equation with the calculated moles.>
<Step 4: Calculate the theoretical yield of AlCl3. Use the moles of the limiting reactant and the stoichiometry of the balanced equation to find the moles of AlCl3 produced.>
<Step 5: Convert the moles of AlCl3 to grams. Use the formula: mass (g) = moles × molar mass (g/mol) to find the theoretical yield in grams.>