Write a molecular equation for the precipitation reaction that oc...

Question

Write a molecular equation for the precipitation reaction that occurs (if any) when each pair of aqueous solutions is mixed. If no reaction occurs, write “NO REACTION.” 1. lithium sulfate and lead(II) acetate 2. strontium nitrate and potassium iodide

Accepted Answer

Identify the ions present in each solution: Lithium sulfate (Li2SO4) dissociates into 2 Li^+ and SO4^2-. Lead(II) acetate (Pb(C2H3O2)2) dissociates into Pb^2+ and 2 C2H3O2^-. Strontium nitrate (Sr(NO3)2) dissociates into Sr^2+ and 2 NO3^-. Potassium iodide (KI) dissociates into K^+ and I^-.. Determine the possible combinations of cations and anions from the mixed solutions: For lithium sulfate and lead(II) acetate, the possible combinations are Li^+ with C2H3O2^- and Pb^2+ with SO4^2-. For strontium nitrate and potassium iodide, the possible combinations are Sr^2+ with I^- and K^+ with NO3^-.. Use solubility rules to determine if any of the new combinations form a precipitate: Lead(II) sulfate (PbSO4) is insoluble, so it will precipitate. All acetates, nitrates, and alkali metal salts are soluble, so no other precipitates form.. Write the balanced molecular equation for the reaction that forms a precipitate: For lithium sulfate and lead(II) acetate, the equation is Li2SO4(aq) + Pb(C2H3O2)2(aq) -> 2 LiC2H3O2(aq) + PbSO4(s). For strontium nitrate and potassium iodide, since no precipitate forms, write 'NO REACTION'.. Conclude with the final molecular equations: 1. Li2SO4(aq) + Pb(C2H3O2)2(aq) -> 2 LiC2H3O2(aq) + PbSO4(s). 2. NO REACTION.