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Ch.20 - Radioactivity and Nuclear Chemistry
Chapter 20, Problem 74

If a 55-gram laboratory mouse is exposed to a dose of 20.5 rad of radiation, how much energy is absorbed by the mouse’s body?

Verified step by step guidance
1
Understand that 1 rad is equivalent to 0.01 joules of energy absorbed per kilogram of tissue.
Calculate the mass of the mouse in kilograms by converting grams to kilograms. (55 grams = 0.055 kilograms)
Use the formula: Energy absorbed (in joules) = dose (in rads) × mass (in kg) × 0.01 J/kg per rad.
Substitute the given values into the formula: Energy absorbed = 20.5 rads × 0.055 kg × 0.01 J/kg per rad.
Perform the multiplication to find the energy absorbed in joules.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Radiation Dose

Radiation dose, measured in units such as rad, quantifies the amount of energy absorbed by a material, typically biological tissue, from ionizing radiation. One rad is defined as the absorption of 100 ergs of energy per gram of tissue. Understanding this concept is crucial for calculating the energy absorbed by the mouse based on its mass and the radiation dose it receives.
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Energy Absorption Calculation

To determine the energy absorbed by an object from radiation, the formula used is: Energy (in ergs) = Dose (in rads) × Mass (in grams). This relationship allows for the straightforward calculation of energy absorbed by multiplying the radiation dose by the mass of the object, which in this case is the laboratory mouse.
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Gibbs Free Energy of Reactions

Unit Conversion

In scientific calculations, it is often necessary to convert units to ensure consistency and accuracy. For example, while energy may be expressed in ergs, it can also be converted to joules (1 erg = 10^-7 joules). Understanding unit conversion is essential for interpreting results and ensuring that calculations align with standard scientific practices.
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Related Practice
Open Question
Calculate the quantity of energy produced per gram of reactant for the fusion of two H-2 (atomic mass = 2.014102 amu) atoms to form He-3 (atomic mass = 3.016029 amu) and one neutron.
Open Question
Calculate the quantity of energy produced per gram of reactant for the fusion of H-3 (atomic mass = 3.016049 amu) with H-1 (atomic mass = 1.007825 amu) to form He-4 (atomic mass = 4.002603 amu).
Textbook Question

A 75-kg human has a dose of 32.8 rad of radiation. How much energy is absorbed by the person's body? Compare this energy to the amount of energy absorbed by the person's body if he or she jumped from a chair to the floor (assume that the chair is 0.50 m from the ground and that all of the energy from the fall is absorbed by the person).

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Open Question
PET studies require fluorine-18, which is produced in a cyclotron and decays with a half-life of 1.83 hours. Assuming that the F-18 can be transported at 60.0 miles/hour, how close must the hospital be to the cyclotron if 65% of the F-18 produced makes it to the hospital?
Textbook Question

Suppose a patient is given 1.55 mg of I-131, a beta emitter with a half-life of 8.0 days. Assuming that none of the I-131 is eliminated from the person's body in the first 4.0 hours of treatment, what is the exposure (in Ci) during those first four hours?

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Textbook Question

Complete each nuclear equation and calculate the energy change (in J/mol of reactant) associated with each (Be-9 = 9.012182 amu, Bi-209 = 208.980384 amu, He-4 = 4.002603 amu, Li-6 = 6.015122 amu, Ni-64 = 63.927969 amu, Rg-272 = 272.1535 amu, Ta-179 = 178.94593 amu, and W-179 = 178.94707 amu). a. _____ + 94Be → 63Li + 42He

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