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Ch.13 - Solutions
Chapter 13, Problem 8

Calculate the freezing point and boiling point of a solution containing 7.55 g of ethylene glycol (C2H6O2) in 85.7 mL of ethanol. Ethanol has a density of 0.789 g/cm³.

Verified step by step guidance
1
Calculate the molality of the solution by first determining the moles of ethylene glycol using its molar mass.
Convert the volume of ethanol to mass using its density, then convert this mass to kilograms.
Use the formula for molality: \( m = \frac{\text{moles of solute}}{\text{kilograms of solvent}} \).
Apply the freezing point depression formula: \( \Delta T_f = i \cdot K_f \cdot m \), where \( i \) is the van't Hoff factor (1 for ethylene glycol), and \( K_f \) is the freezing point depression constant for ethanol.
Apply the boiling point elevation formula: \( \Delta T_b = i \cdot K_b \cdot m \), where \( K_b \) is the boiling point elevation constant for ethanol.