Instead of having three carbons in a row, the three carbons of the hydrocarbon cyclopropane form a ring, as shown in the following perspective drawing:

Cyclopropane was at one time used as an anesthetic, but its use was discontinued, in part because it is highly flammable.

a. What is the empirical formula of cyclopropane?

b. The three carbon atoms are necessarily in a plane. Is the entire molecule in a plane (flat)?

c. Can you use mass spectrometry to tell the difference between cyclopropane and propane, assuming the technique is reliable to 0.1 amu?

d. What change would you make to the structure shown to draw cyclopropanol?

e. How many isomers of cyclopropanol are there (ignore wedge positions for the purposes of this problem)?