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Ch.6 - Thermochemistry
Chapter 6, Problem 117

A copper cube with an edge measuring 1.55 cm and an aluminum cube with an edge measuring 1.62 cm are both heated to 55.0 °C and submerged in 100.0 mL of water at 22.2 °C. What is the final temperature of the water when equilibrium is reached? (Assume a density of 0.998 g/mL for water.)

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1
Calculate the volume of each cube using the formula for the volume of a cube: \( V = a^3 \), where \( a \) is the edge length.
Determine the mass of each cube using the formula \( m = \rho \times V \), where \( \rho \) is the density of the material. Use the densities: copper (8.96 g/cm³) and aluminum (2.70 g/cm³).
Calculate the heat lost by each metal cube using the formula \( q = m \times c \times \Delta T \), where \( c \) is the specific heat capacity (copper: 0.385 J/g°C, aluminum: 0.897 J/g°C) and \( \Delta T \) is the change in temperature.
Calculate the heat gained by the water using the formula \( q = m \times c \times \Delta T \), where \( m \) is the mass of the water (100.0 mL \( \times \) 0.998 g/mL), \( c \) is the specific heat capacity of water (4.18 J/g°C), and \( \Delta T \) is the change in temperature.
Set the heat lost by the metal cubes equal to the heat gained by the water and solve for the final temperature \( T_f \) when equilibrium is reached.