Cyclopropane and propylene are isomers that both have the formula C₃H₆. Based on the molecular structures shown, which of these isomers would you expect to have the higher standard molar entropy at 25 °C?

Video transcript

welcome back everyone in this example, we have cyclo butane and beauty in our customers that have different arrangements, but the same formula C. Four H eight. We're told that at 25 degrees Celsius, which of these ice members have a higher standard molar entropy based on their molecular structure. So we want to recognize that cycle. Butane and beauty are both gaseous molecules, so they will not be able to have a lattice effect at 25°C. We also should recognize that we have less branching associated with our molecule beauty. We just have these two branches of CH three groups here on beauty and therefore we would have more free rotation around our carbon carbon bonds on Beauty. In comparison to cyclo butane, which has a more rigid structure of branches. And because we have greater free rotation of these carbon carbon single bonds, we would say that we have formally greater emotional freedom, which relates to a higher absolute entropy. So recall that entropy describes disorder and therefore we would have a higher standard Mueller entropy. And so we would confirm that between these two structures. Beauty in is going to be the one with the higher standard molar entropy based on its molecular structure, which is less branched and allows for more free rotation around the carbon carbon single bonds. So, Beauty is our final answer. I hope everything I reviewed was clear. If you have any questions leave them down below and I'll see everyone in the next practice video