Given the following standard reduction potentials, determine Ksp for Hg2Cl2(s) at 25 °C.
Hg22+ (aq) + 2 e– → 2 Hg (l) E°red = + 0.789 V
Hg2Cl2 (s) + 2 e– → 2 Hg (l) + 2 Cl – (aq) E°red = + 0.271 V
-1.3 x 104 J/mol
-2.9 x 103 J/mol
+4.3 x 105 J/mol
+7.7 x 107 J/mol
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