What is the pressure in a 10.0 L cylinder filled with 0.448 mol of nitrogen gas at a temperature of 315 K?

Verified step by step guidance

1. Identify the ideal gas law equation: \( PV = nRT \).
2. Rearrange the equation to solve for pressure \( P \): \( P = \frac{nRT}{V} \).
3. Identify the values given in the problem: \( n = 0.448 \text{ mol} \), \( V = 10.0 \text{ L} \), \( T = 315 \text{ K} \).
4. Use the ideal gas constant \( R = 0.0821 \text{ L atm mol}^{-1} \text{ K}^{-1} \).
5. Substitute the values into the equation: \( P = \frac{(0.448 \text{ mol})(0.0821 \text{ L atm mol}^{-1} \text{ K}^{-1})(315 \text{ K})}{10.0 \text{ L}} \).