Determine the elimination product form in the following reaction. Now another name for a dehydration reaction is an elimination reaction. Here we have our alcohol reacting with sulfuric acid, so we know we're trying to create an alkene at the end.

Here is our carbon or alcohol carbon with its OH and here are the neighboring carbons. This neighboring carbon here is making two bonds, so it has two hydrogens. This neighboring carbon here has makes 2 bonds, so it has two hydrogens. We don't see in this process we're going to lose water. So lose an OH from the alcohol carbon and lose an H from one of its neighboring carbons.

Here I decide to lose it from this side, but it could equally happen on the other side because those two neighboring carbons are the same. They both have two hydrogens. So here we're going to lose water and when we lose water that's going to force those two carbons to make a double bond with one another in order for them to continue to make four bonds.

O we're al keen would look like this and this would be cyclohexene. This would be our elimination or dehydration product.