Given the following standard reduction potentials, determine Ksp for Hg2Cl2(s) at 25 °C.
Hg22+ (aq) + 2 e– → 2 Hg (l) E°red = + 0.789 V
Hg2Cl2 (s) + 2 e– → 2 Hg (l) + 2 Cl – (aq) E°red = + 0.271 V
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